Chemistry, asked by saquibhasib203p5ia2w, 1 year ago

The work function of a photoelectric material is 3.3 eV. Its threshold frequency will be

Answers

Answered by priya635
23
work function= planksconstant x threshold frequency

by substituting the given value we get the answer that

Threshold frequency= 4.98x10 power 33

saquibhasib203p5ia2w: can u send me the full solution
Answered by RomeliaThurston
27

Answer: The threshold frequency of the material comes out to be 7.97\times 10^{14}s^{-1}

Explanation:

Work function for a material is defined as the minimum amount of energy required to remove an electron to infinity from the surface of the material.

Mathematically,

W=h\nu_o

where,

W = work function of the material = 3.3eV=3.3\times 1.602\times 10^{-19}J     (Conversion factor:  1eV=1.602\times 10^{-19}J )

h = Planck's constant = 6.626\times 10^{-34}Js

\nu_o = Threshold frequency of the material

Putting values in above equation, we get:

3.3\times 1.602\times 10^{-19}J=6.626\times 10^{-34}Js\times \nu_o\\\\\nu_o=7.97\times 10^{14}s^{-1}

Hence, the threshold frequency of the material comes out to be 7.97\times 10^{14}s^{-1}

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