Question

The work function of cesium is 2.14 eV. The threshol
frequency of for cesium (h = 6.63 x 10-34 Js) is
(a) 5.16 x 1014 Hz
(b) 5.45 x 1014 Hz
(c) 6.12 x 1014 Hz
(d) 6.56 x 1014 Hz​

Answer 1

Explanation:

a) W=hv

Where W = work function

h = planck constant

v = threshold frequency

v=

h

W

=

6.6×10

−34

2.14×1.6×10

−19

=5.2×10

14

hertz

b) Wavelength of incident photon =

ev

hc

+W

By substituting the values we get

Wavelength = 4.5×10

−7

m