Question

the work function of metal 2.2ev. find the flux density of the magnetic field applied perpendicular to the direction of motion of ejected photoelectrons to make them trace a circle of radius 0.2m when light of wave length 300nm is incident on the metal?

Answer 1

Answer:

Magnetic flux density,B = ¤ / A

where, ¤ = work function

A = area of surface

So, B = $2.2 \times 1.6 \times {10}^{ - 19} \div 2 \times \pi \times {0.2}^{2}$

By solving, B = $1.4 \times {10}^{ - 18}$ T

hope this will help you