The work function of metal surface is 5 eV. If photon of wavelength 2480 Å strikes on the metal surface, then maximum kinetic energy (approx.) of photoelectron is
Answers
Step-by-step explanation:
Energy of incident radiation is E=
λ
hc
=
3×10
−7
6.6×10
−34
×3×10
8
=6.6×10
−19
J.
Also, work function is ϕ=2×1.6×10
−19
J=3.2×10
−19
J.
Hence, maximum kinetic energy of emitted photo electrons will be 6.6×10
−19
J−3.2×10
−19
J=3.4×10
−19
J.
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The kinetic energy of the photoelectron is zero.
Given,
Work function of the metal=5 eV
Wavelength of incident light=2480 Å.
To find,
the maximum kinetic energy (approx.) of photoelectron.
Solution:
- Work function(W) of a metal is the minimum energy that is required to surface electrons.
- It is measured in eV.
- When the energy of the incident light E is greater than the work function of the metal that it strikes, the electrons make best use of the incident energy and come out with kinetic energy.
- It is represented by the following expression:
- .
- This equation is known as Einstein's photoelectric equation.
It can further be written as:
where,
h-Plank's constant
c-speed of light
λ-wavelength.
There is an another formula which can be used to find E or W
(in ev), it is given as:
The energy of the incident light will be:
The kinetic energy of the photoelectron will be:
Hence, the kinetic energy is 0.
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