Question

The work of a student to factorise (15a⁴ − 70a²) is shown as: 15a⁴ − 70a² = (3 × 5 × a × a × a × a) − (2 × 5 × 7 × a ×a) = 5(3 × a × a × a × a − (2 × 7 × a × a)) = 5(3a⁴ − 14a²). Is his work correct?

1️⃣ No
2️⃣ Yes​

Answer 1

Step-by-step explanation:

no

because in his second step he written 5 as common but 5 is not common and and ans is 5a^2(3a^2-14) hope is useful

Answer 2

Answer:

No this is not correct

thanku