Question

The x-coordinate of a point P is twice its
y-coordinate. If P is equidistant from Q(2, -5)
and R(-3, 6), find the co-ordinates of P.​

Answer 1

it's simple dude......

let the ordinates of P be y the then abcissa will be 2y

use distance formula now

{(2y-2)^2+(y+5)}^1/2={(2y+3)^2+(y-6)^2}^1/2

4y^2+4-8y+y^2+25+10y=4y^2+9+12y+y^2+36-12y

4-8y+25+10y=9+12y+36-12y

2y-6y+=45-29

4y=16

y=4

hence

coordinates are(8,4)

{easiest question}