The x-coordinate of a point P is twice its y-coordinate if P is equidistant from Q(2,-5)and R(-3, 6), find the coordinates of P.
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Let P(x,y) is the required point
.Let Q(2,−5) and R(−3,6) are the given points.
Now, PQ = PR
⇒PQ2 = PR2
⇒(x−2)2+(y+5)2 = (x+3)2+(y−6)2
[Using distance formula]
⇒x2+4−4x+y2+25+10y = x2+9+6x+y2+36−12y
⇒−4x+10y+29 = 6x−12y+45
⇒−10x+22y−16 = 0
⇒−10(2y) + 22y = 16
=2y =16
=) y =8
now x=2y = 2 × 8 = 16
So coordinates of required point
P are P(16,8)
.Let Q(2,−5) and R(−3,6) are the given points.
Now, PQ = PR
⇒PQ2 = PR2
⇒(x−2)2+(y+5)2 = (x+3)2+(y−6)2
[Using distance formula]
⇒x2+4−4x+y2+25+10y = x2+9+6x+y2+36−12y
⇒−4x+10y+29 = 6x−12y+45
⇒−10x+22y−16 = 0
⇒−10(2y) + 22y = 16
=2y =16
=) y =8
now x=2y = 2 × 8 = 16
So coordinates of required point
P are P(16,8)
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