the X- coordinate of a point P is twice its Y- coordinate. if P is equidistant from Q(2, -5) and R(-3, 6), find the coordinates of P
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19
Answer:
8
Step-by-step explanation:
Let the point P be (2k, k), Q(2,-5), R(-3, 6)
PQ = PR …Given
PQ² = PR² …[Squaring both sides
(2k – 2) ²+ (k + 5)² = (2k + 3)² + (k – 6)²…Given
4k² + 4 – 8k + k² + 10k + 25 = 4k² + 9 + 12k + k² – 12k + 36
⇒ 2k + 29 = 45
⇒ 2k = 45 – 29
⇒ 2k = 16
⇒ k = 8
Hope it is helpful.
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