The x intercept of the line 4y – 3x + 11 is
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Equation of the given line is 3x – 4y + 11 = 0
Slope of this line y = mx + c
4y = 3x + 11
y = ¾.x + 11/4
m1 = ¾
Let m2 be the slope of the line which is perpendicular to the given line then
m1m2 = - 1
¾ m2 = - 1
⇒ m2 = - 4/3
Also, Y-intercept c = 4/3
Equation of the required line
y = m2x + c
y = - 4/3 x + 4/3
⇒ 3y = - 4x + 4
⇒ 4x + 3y – 4 = 0
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