Question

the zero of polynomial 6y(y-2)(y+3) are​

Answer 1

Answer:

Let p(y) = 6y2-7y+2 Read more on Sarthaks.com - https://www.sarthaks.com/36230/if-and-are-the-zeros-of-the-polynomial-6y-7y-find-quadratic-polynomial-whose-zeros-are-and

Answer 2

As per the data given in the above question.

We have to find out the zero of polynomial of given equation.

Step-by-step explanation:

Given ,

$6y(y-2)(y+3)$

Multiply 6y to (y-2)

$(6y²-12y)(y+3)$

Again multiply (y+3) by (6y²-12y)

$y(6y²-12y) + 3(6y²-12y)$

$6y³-12y²+18y²-36y$

$6y³-6y²-36y = 0$

Now take 6y common

$6y (y²-y-6)=0$

$6y (y²-3y+2y-6)=0$

$6y(y-2)(y+3) = 0$

So ,take individual terms to equal 0

$6y=0 \: or \: y=0$

$y-2=0 \: or \: y=2$

$y+3=0 \: or \: y=-3$

Hence,

zero of polynomial 6y(y-2)(y+3) are 0,2 and -3.

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