Question

The zero of the quadratic polynomial x*x+88x+125 are what

Answer 1

just apply the quadratic formula
$d = {b}^{2} - 4ac \\ and \: then \\ roots = \frac{ - b + - \sqrt{d} }{2a}$

Answer 2

Answer:

The roots are $x=-44+\sqrt{1811},-44-\sqrt{1811}$

Step-by-step explanation:

Given : Polynomial - $x^2+88x+125$

To find : The zero of the quadratic polynomial

Solution :

Equation $x^2+88x+125=0$

Solving by discriminant method  

General form - $ax^2+bx+c=0$

$D=b^2-4ac$

Solution is $x=\frac{-b\pm\sqrt{D}}{2a}$

Comparing with our equation,

where a=1 , b=88, c=125

$D=b^2-4ac$

$D=(88)^2-4(1)(125)$

$D=7744-500$

$D=7244$

Solution is $x=\frac{-b\pm\sqrt{D}}{2a}$

$x=\frac{-(88)\pm\sqrt{7244}}{2(1)}$

$x=\frac{-88\pm2\sqrt{1811}}{2}$

$x=-44\pm\sqrt{1811}$

Therefore, The roots are $x=-44+\sqrt{1811},-44-\sqrt{1811}$