Math, asked by madhuguddi79, 8 months ago

the zeroes of polynomial x^2-x-2 are​

Answers

Answered by Anonymous
2

p(x) = x² - x - 2 = 0

Let,

  • a = 1
  • b = -1
  • c = -2

Sum of the zeroes : α + ß = -b/a = -(-1)/1 = 1

Product of the zeroes : αß = c/a = -2/1 = -2

Step-by-step explanation:

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