Question

The zeroes of the following polynomial: 3 X square + 15 X + 12​

Answer 1

Answer:

x= -4 or -1

Step-by-step explanation:

3x^2 + 15x + 12 =0

taking the as common in first eqn

3 (x^2 + 5x +4) =0

(x^2 + 5x +4) =0/3

x^2 + 5x +4 =0

(x^2 + 4x)(+x+4)= 0

x(x+4) +1(x+4)=0

(x+4)(x+1)=0

(x+4)=0 (x+1)=0

x= -4 x= -1

Answer 2

3 X square + 15 X + 12=0

3(x square +5x + 4)=0

x square +5x + 4= 0

x square +4x+x+4=0

x(x+4) +1(x+4)

(x+4) (x+1)

(x+4) (x+1) ate the zeroes of the polynomial: 3 X square + 15 X + 12