Question

the zeroes of the following polynomials 3x^2+15x+12​

Answer 1

Step-by-step explanation:

please follow me

p(x)=3x

3

+16x

2

+15x−18

x=

3

2

x−

3

2

=0

3

3x−2

=0

⇒3x−2=0

x

2

+6x+9

____________________

3x−2)3x

3

+16x

2

+15x−18

3x

2

−2x

2

(−) (+)

______________________

18x

2

+15x−18

18x

2

−12x

____________________

27x−18

27x−18

________________

0

Answer 2

Answer:

Let the P(x) be(x+1)

x+1=0

x=-1

by putting,

p(-1)=3(-1)*2+15(-1)+12

=3-15+12

=-12+12

=0

so the zero of the polymial is (x+1)