the zeroes of the following polynomials 3x^2+15x+12
Answers
Answered by
0
Step-by-step explanation:
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p(x)=3x
3
+16x
2
+15x−18
x=
3
2
x−
3
2
=0
3
3x−2
=0
⇒3x−2=0
x
2
+6x+9
____________________
3x−2)3x
3
+16x
2
+15x−18
3x
2
−2x
2
(−) (+)
______________________
18x
2
+15x−18
18x
2
−12x
____________________
27x−18
27x−18
________________
0
Answered by
2
Answer:
Let the P(x) be(x+1)
x+1=0
x=-1
by putting,
p(-1)=3(-1)*2+15(-1)+12
=3-15+12
=-12+12
=0
so the zero of the polymial is (x+1)
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