Question

The zeroes of the polynomial f(u)=4u²+8u are
(a)0,-2 (b)0,2 (c)1,2 (d)1,-2​

Answer 1

Answer:

Let p(x) = 4u(square)+8u

4usquare+8u=0

4u(u+2) =0

4u=0, u+2=0

u=0, u= -2

ans= (0, -2)

Answer 2

Step-by-step explanation:

(a ) is the zeroes of the polynomial