Question

The zeroes of the polynomial f(x) = 2x³ - 9x² + x + 12 are
3
(1) 1, 4,-3/2
(2) -1, 4,3/2
(3) -1, 4,-3/2
(4) 1 ,- 4,-3/2​

Answer 1

Answer:

by substituting the values

so, f(-1)= -2-9-1+12=0

f(4)= 128-144+4+12=0

f(-3/2)= -27/4-81/4-3/2+12=0

so option 3 is correct

Answer 2

Answer:

1.f(1)=2×1³-9×1²+1+12=0

=2-9+1+12=0

=15-9=0

=6≠0

no

2.f(4)=2×4³-9×4²+4+12=0

=128-144+16=0

=0=0

yes

3.f(-3/2)=2×(-3/2)³-9×(-3/2)²+(-3/2)+12=0

=2×-27/8-9×9/4-3/2+12=0

=-27/4-81/4-3/2+12=0

=-108/4-3/2+12=0

=-27/2-3/2+12=0

=-27-3/2+12=0

=-29/2+12≠0

no

so answer is -1,4,3/2