Math, asked by babligupta36191, 9 months ago

The zeroes of the polynomial X^2 +1/6x - 2 arc

Answers

Answered by ipsita

0

Answer:

Step-by-step explanation:

X²+1/6x-2

=6x2+x-12

=6x²+9x-8x-12

=3x(2x+3)-4(2x+3)

=(3x-4)(2x+3)

X=4/3 OR x=-3/2

Mark BRAINLIEST

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