Question

The zeroes of the polynomial x^2 -3x -m(m+3) are
A)m,m+3 B)-m,m+3
C)m,-(m+3) D)-m,-(m+3)
No spamming with nonsense answers

Answer 1

Answer:B

Use a.c method here

a×c=-m(m+3)

b=-3

Two numbers are m and -(m+3)

$(x+m)(x-m-3)=0$

∴ $x=-m$ or $x=m+3$

So it's B