The zeroes of the quadratic polemical x^2-7x+10 are
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Answer:
x^2-7x+10
=x^2-2x-5x+10
=x(x-2)-5(x-2)
=(x-2)(x-5)
(x-2)=0 or (x-5)=0
=>x=2. =>x=5
the zeroes of the quadratic polynomial are 2 and 5
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