Question

The zeroes of the quadratic polynomial x 2 + 36x + 99 are : (a) both positive (b) both negative (c) one positive and one negative (d) both equal

Answer 1

Required Answer:-

Question:

• Find the nature of roots of quadratic equation.

Solution:

We have,

➡ x² + 36x + 99 = 0

➡ x² + 33x + 3x + 99 = 0

➡ x(x + 33) + 3(x + 33) = 0

➡ (x + 3)(x + 33) = 0

By zero product rule,

➡ Either x + 3 = 0 or x + 33 = 0

Hence,

➡ x = -3, -33

★ Hence, the roots of the given quadratic equation are both negative. Option B is the answer for this question.

Answer:

• Both roots of the given equation are negative.

Learn More:

• Discriminant of quadratic equation = b² - 4ac
• If D > 0, Roots are real and unequal.
• If D = 0, Roots are real and equal.
• If D < 0, Roots are imaginary and unequal.