Question

The zeroes of the quadratic polynomial x square + 99x + 127 are

(A) Both positive
(B) both negative
(C) one positive and one negative
(D) both equal

Explain it in simple way .

Answer 1

To find the answer let we use the Discriminant formula.

Discriminant = b² - 4 ac

= (99)² - 4(1)(127)

= 9801 - 508

= 9293

Hence they give out roots of both signs and 9293>0 which means the roots 

are real and distinct.
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And so option (c) is equal hence they give out both positive and negative 

zeroes.
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