Question

The zeroes of the quadratic polynomial x2+99x+127 are: A. both positive B. both negative C. one positive and one negative D. both equal​

Answer 1

p(x) =x2 + 99x + 127.

On comparing p(x) with ax2 + bx + c, we get

a = 1, b = 99 and c = 127  

ref to attachment ..

Hence, both zeroes of the given quadratic polynomial p(x) are negative

Answer 2

Given polynomial is x^2+99x+27

Sum of zeroes =−99

Product of zeroes =27

∵ Sum of zeroes is negative and product of zeroes is positive, this is only possible if both should be negative.

∴ Both zeros will be negative.

Option B is correct.