Question

The zeroes of x2-2x -8 are:​

Answer 1

Answer:

${x}^{2} - 2x - 8 = 0 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0 \\ (x - 4)(x + 2) = 0 \\ x = 4 \: and \\ \: - 2$

Answer 2

Answer:

4 ,-2

Step-by-step explanation:

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