the zeros of 6 x square - 7 x - 3
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=6x2-7x-3
=6x2-9x+2x-3
=3x(2x-3)+1(2x-3)
=(3x+1)(2x-3)
=(3x+1)=0;(2x-3)=0
=x=(-1/3) & x=(3/2)
=6x2-9x+2x-3
=3x(2x-3)+1(2x-3)
=(3x+1)(2x-3)
=(3x+1)=0;(2x-3)=0
=x=(-1/3) & x=(3/2)
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