Math, asked by ashwinmali24, 7 months ago

the zeros of P(x)2x²-8x+6 are​

Answers

Answered by rajeevr06
1

Answer:

2 {x}^{2} - 8x + 6 = 0 \\ {x}^{2} - 4x + 3 = 0 \\ {x}^{2} - 3x - x + 3 = 0 \\ x(x - 3) - 1(x - 3) = 0 \\ (x - 3)(x - 1) = 0 \\ x = 1 \: \: or \: \: 3 \\ ans.

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