Question

the zeros of P(x)2x²-8x+6 are​

Answer 1

Answer:

$2 {x}^{2} - 8x + 6 = 0 \\ {x}^{2} - 4x + 3 = 0 \\ {x}^{2} - 3x - x + 3 = 0 \\ x(x - 3) - 1(x - 3) = 0 \\ (x - 3)(x - 1) = 0 \\ x = 1 \: \: or \: \: 3 \\ ans.$