Question

the zeros of p(z)=z(square)-27are​

Answer 1

$\huge{\boxed{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Answer:-}}}}}\mid}}}}$

${ \underline {\underline{ \star \: given - }}}$

$p(z) = {z}^{2} - 27.$

$\rightarrow \: {z}^{2} - 27. \\ \\ \rightarrow \: {z}^{2} = 27. \\ \\ \rightarrow \: z = 3\sqrt{3} . \: \: \: \: \: and \: \: \: - 3\sqrt{3}$

$<marquee>Follow me$

$<marquee>Mark as Brainliest$

Answer 2

Answer:

-27a^24

Step-by-step explanation:

27a^1×a^1 4 calculate the product

-27a^1+1 4

add number..