Question

The zeros of the polynomial 6 y ( y + 2 )( y – 3 ) ​

Answer 1

Answer:

Hey!! Ur answer:

$6y(y + 2)(y - 3) \\ =( 6 {y}^{2} + 12y)(y - 3) \\ = 6 {y}^{3} + 12 {y}^{2} - 18 {y}^{2} - 36y \\ = 6 {y}^{3} - 6 {y}^{2} - 36y = 0 \\ = >6y( {y}^{2} - y - 6) = 0$

Step-by-step explanation:

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Answer 2

Answer:

Construct a quadrilateral ABCD, where

Construct a quadrilateral ABCD, whereAB = 4 cm, BC = 5 cm, CD = 6.5 cm and angle B = 105° and angle C = 80°