Question

The zeros of the polynomial p(x)=x^2+x-6

Answer 1

Answer:

x ² + x - 6

x ² + 3x - 2x - 6

x ( x + 3 ) -2 ( x + 3 )

( x - 2 ) ( x + 3 )

x - 2 = 0      x + 3 = 0

x = 2            x = -3

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Answer 2

Given:

p(x)=x^2+x-6

To find:

The zeroes

Solution:

The required zeroes are -3 and 2.

We can factorize the given equation and obtain the polynomial's zeroes.

On factorizing, we get

p(x)=$x^{2}$+x-6

=$x^{2}$+3x-2x-6

=x(x+3)-2(x+3)

=(x+3)(x-2)

Now we will equate these factors with 0 to obtain the roots.

So, (x+3)=0 and (x-2)=0.

x= -3, x=2

Therefore, the required zeroes are -3 and 2.