Question

the zeros of the polynomials h(x) =(x-5)(x^2-x-6) are
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Answer 1

Answer:

$h(x) = (x - 5)( {x}^{2} - x - 6) \\ = (x - 5)( {x}^{2} + 2x - 3x - 6) \\ = (x - 5)(x( x + 2) - 3( x + 2)) \\ = (x - 5)(x + 2)(x - 3)$

Hence, the answer is -3,-2,and 5.

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Answer 2

Answer:

5,3,-2

Step-by-step explanation:

h(x) = (x-5)(x^2-x-6)

by, splitting middle term in x^2 -x -6

x^2 +2x -3x -6

x(x+2) -3(x+2)

(x-3) (x+2)

hence , h(x) = (x-5)(x-3)(x+2)

so zeros = 5,3,-2