Question

. The zeros of the quadratic polynomial having zeros as -2 and -5 is​

Answer 1

let the zeroes be a and b

a=(-15)

b=?

sum of zeroes(a+b)=42

-15+b=42

b=57

therefore second zero is 57

product of zeroes(ab)

=(-15)x57

=(-855)

req. quadratic polynomial

=k[x2 -(a+b)x +(ab)]

=k[x2 -(-15)x +(-855)]

=k[x2 +15x -855] where k is non zero constant

Answer 2

Answer:

$x {}^{2} + 7x + 10 = 0$

Step-by-step explanation:

$let \: \alpha = - 2$

$let \: \beta = - 5$

$formula \: of \: quadratic \: equation \: is \\ \: x{}^{2} - ( \alpha + \beta )x + \alpha \beta = 0$

Then

$x {}^{2} - ( - 7)x + 10 = 0$

$x {}^{2} + 7x + 10 = 0$I THINK IT IS HELPFUL TO YOU