Math, asked by PRACHISHETTY6776, 1 year ago

the zeros of the quadratic polynomial x^2+88x+125

Answers

Answered by maheshv22
5

 {x}^{2}  + 88x125 \\ x =  - b +  \sqrt{ {b}^{2}  -  4ac} \div 2a \\ where \: a = 1 \\ b = 88 \\ c = 125 \\ we \: get answer

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