Question

the zeros of the quadratic polynomial X square + 99 X + 127

Answer 1

Hi ,

We know that,

In a quadratic expression ax²+ bx + c

If a , b , c will have the same sign

then the both zeroes of the

expression are negative

Compare given expression

x² + 99x + 127 with ax² + bx + c ,

a = 1 , b = 99 ,c = 127

All are positive sign ,

Therefore ,

The expressions both zeroes has

negative sign.


I hope this helps you.

Answer 2

HEY Buddy......!! here is ur answer

Given that the quadratic equation is...

x²+99x+127

On comparing with the standard quadratic equation ax²+bx+c

Here, a = 1, b = 99 and c = 127

As we know that Shridharacharya Formula....

x = [-b(+-)√b²-4ac]/2a

=> x = [-99(+-)√(99)²-4(1)(127)]/2(1)

=> x = [-99(+-)√9801-508]/2

=> x = [-99(+-)√9293]/2

=> x = [-99(+-)96.4]/2

On taking (+) sign,

=> x = (-99+96.4)/2

=> x = -2.6/2 = -1.3

On taking (-) sign,

=> x = (-99-96.4)/2

=> x = -195.4/2

=> x = -96.2

So, both the zeroes are negative.

I hope it will be helpful for you...!!

THANK YOU ✌️✌️

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