Question

The zeros of the quadratic polynomial x2 +99x+127 is

Answer 1

Answer:

In this equation have two zeroes are -1.3 and -97.7 . Both are negative zeroes.

Explanation:

$x2 + 99x + 127$

a = 1 , b = 99 , c = 127

D = b2 - 4ac

= (99)^2 - 4 ×1×127

= 9801 - 508

= 9293

√D = 9293

= 96.4

then we applied quadratic formula

x= -b _+ √D /2a

x= -99 _+ 96.4 /2

= -99 + 96.4 /2 , -99 - 96.4

= -2.6 /2. , -195.4/2

= - 1.3. , - 97.7

hence these are the zeroes of quadratic formula.