Question

The zeros
of the
quadric polyonimal
x²+88 X+ 125 are.​

Answer 1

Answer:

The answer is as follows:-

Step-by-step explanation:

Both the zeros are Negative

Answer 2

Solution : Let αandβ be the zeros of the given polynomial. Then, α+β=-88andαβ=125. This happens when αandβ are both negative.