Question

the zeros of, xsquare-8x+13
$x{}^{2} - 8x + 13$
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Answer 1

Answer:

In general the square (x+a)2=x2+2ax+ a2. If (−8x) is the second term of a square of this form then a=−4 and a2=16. x2−8x+13=0. (x−4)2−16+13= 0.

Answer 2

Answer:

x^2-8x+13=0

solving using discriminant method ,

d=b^2-4ac=64-52=12

x=-b+√d/2a

8+2√3/2

2(4+√3)/2

4+√3

so one zero is 4+√3 and other is 4-√3