Question

thebsum of three consecutive multiples of 8 is 888. find the multiples.

Answer 1

Hello here is your answer

Let three consecutive multiples of 8 are =x, x+8,x+16
A/Q
x+x+8+x+16=888
3x+24=888
3x=888-24
3x=864
x=864/3
x=288

So three consecutive multiples of 8 are.
x=288
x+8=296
x+16=304

Hope it helps you

Answer 2

$<b>$Let the three multiples be 8n, 8n + 8 and 8n + 16

Their sum = 888


A/q,

8n + 8n + 8 + 8n + 16 =
888

24n + 24 = 888

24 (n + 1) = 888

(n + 1) = $\frac{888}{24}$

(n + 1) = 37

n = 36




1st number => 8n => 8 × 36 => 288



2nd number => 8n + 8 => 8 × 36 + 8 => 296



3rd number => 8n + 16 => 8 × 36 + 16 = 304