Question

their are 49 houses numbered from 1 to 49 their is house X such that the sum of the houses before X is equal to sum of the no. of houses preceding X find value of x​

Answer 1

Answer:

x=35

Step-by-step explanation:

According to the question

S₍ₓ₋₁₎ = S₄₉-Sₓ

∴$\frac{x-1}{2}$[1+x-1] = $\frac{49}{2}$[1+49] - $\frac{x}{2}$[1+x]

x(x-1) = 49×50 - x(1+x)

x²-x = 49×50 -x -x²

2x² = 49×50

x² = 49×25

x = 7×5

x = 35