then {f^2-f^2}÷ F. please answer
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Answered by
1
Step-by-step explanation:
Differentiate 3f(x)−2f(x1)=x with respect to x,
3f′(x)−2f′(x1)(−x21)=1
3f′(x)+x22f′(x1)=1 (1)
Put x=2 in equation (1),
3f′(2)+222f′(21)=1
3f′(2)+21f′(21)=1 (2)
Put x=21 in equation (1),
3f′(21)+(
Answered by
2
Step-by-step explanation:
3f(x) - 2f(x1) (-x21) = 1
3f(x) + x22f (x1) = 1
x=21
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