then its ZC
is represented by X
यदि ABC वक्र को -7x+12, द्वारा दर्शाया गया है तो इसके शून्यांक होंगे।
(0(2,-3)
(ii) 3,4)
(iii) (4,-5)
(IV)
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Step-by-step explanation:
Step-by-step explanation:3 is the answer now what you want
Answered by
1
Given : ABC वक्र को x²-7x+ 12, द्वारा दर्शाया गया है
To Find : शून्यांक
(i) (2,-3)
(ii)3,4)
(iii) (4,-5)
(IV)3,-5
Solution:
x²-7x+ 12,
= x² - 4x - 3x + 12
= x(x - 4) - 3(x - 4)
= (x - 3)(x - 4)
x - 3 = 0=> x = 3
x - 4 = 0 => x = 4
शून्यांक 3 , 4
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