Question

THEOREM 12.1
Any point on the right bisector of a line segment is dan mendon se
the segment
Given:
A line MN intersects the line segment AB ar
the point R such that MN is the right bisector
of AB which cuts AB at R. Let P be a point
on MN.
Construction:
Join P to the points A and B.
To Prove
Pis equidistant from A and Biem PA=mPB
Readus
Proof:
Statements
In APRA APRB
PRE PR
(Common)​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

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