Theorem 2: In a parallelogram, opposite sides are equal
Prove that
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Restatement: ABCD is a parallelogram
To prove: AB = DC ( opposite sides of a parallelogram)
and AD = BC ( opposite sides of a parallelogram )
Construction: We join AC
Proof: In triangle ABC and triangle ADC
AB is parallel to CD , AC is the transversal
angle BAC = angle ACD ( alternate angles )
AD is parallel to BC , AC is the transversal
angle DAC = angle BCA ( alternate angles)
AC = AC ( common side )
Therefore, triangle ABC is congruent with triangle ADC (ASA)
Therefore AB = CD (CPCT)
AD = BC (CPCT)
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