Question

Theorem 8.9 : The line segment joining the mid-points of two sides of a in
You will see that converse of the above theorem is also true which is state!
So, you arrive at the
is parallel to the third side.
You can prove this theorem using the following
clue:
Observe Fig 8.25 in which E and Fare mid-points
of AB and AC respectively and CD | BA.
A AEFE A CDF (ASA Rule)
So,
EF = DF and BE = AE = DC (Why?)
B
Therefore, BCDE is a parallelogram. (Why?)
This gives EF || BC.
In this case, also note that EF ED =
-
BC.
2
2
Can you state the converse of Theorem 8.9? Is the converse true?

Answer 1

Answer:

9.2

true

Step-by-step explanation:

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