Question

theorem of perpendicular drawn from a centre of a circle on its chord bisects the chord

Answer 1

Given - op is perpendicular to ab which is a chord of a circle

prove that - ap = pb

In triangle oap and apb

op=op ( common )

oa=ob ( equal raddi)

by Rhs

triangle oap congurent to oap

by cpct ap=pb

hence proved that the perpendicular to the chord bisects the chord

Answer 2

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