theoretically prove that the sum of interior angles of a triangle is 180
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Step-by-step explanation:
To prove the above property of triangles, draw a line \overleftrightarrow {PQ} parallel to the side BC of the given triangle. Thus, the sum of the interior angles of a triangle is 180°.
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Hi!
Here is the answer to your query.
Consider a triangle PQR and ∠1, ∠2 and ∠3 are the angles of ΔPQR (figure shown below). We need to prove that ∠1 + ∠2 + ∠3 = 180°.
XPY is a line.
∴∠4 + ∠1 + ∠5 = 180° … (1)
But XPY || QR and PQ, PR are transversals.
So, ∠4 = ∠2 and ∠5 = ∠3 (Pairs of alternate angles)
Substituting ∠4 and ∠5 in (1), we get
∠2 + ∠1 + ∠3 = 180°
∴∠1 + ∠2 + ∠3 = 180°
Cheers!
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