Question

There are 10 cards numbered 1 to 10. A card is chosen at random. What is the probability of getting a card bearing number which is (i) a multiple of 4 (ii) a one digit number (iii) a 2-digit number (iv) a 2-digit number less than 10?

Answer 1

Answer:

Step-by-step explanation:

(i) 1/10

(ii) 4/10 = 2/5

(iii) 6/10 = 3/5

(iv) 9/10

Answer 2

Answer:

1- 1/5,2-9/10,3-1/10,4-0/10=0