Math, asked by raltaf9357, 1 year ago

There are 10 lamps in a hall. each one of them can be switched on independently. the number of ways in which the hall can be illuminated is

Answers

Answered by Rajnishkd
219
RD SHARMA... right..?.

Well answer is 1023 ways..
Total number of lamps =10

Since at least one lamp is to be kept switched on

The total number of ways are

10C1+10C2+....+10C10

⇒2^10−1

⇒1024−1

⇒1023 ways...



Don't forget to mark itvas brainy..


Answered by gayatrikumari99sl
1

Answer:

The number of ways in which the hall can be illuminated is 1023 .

Step-by-step explanation:

Explanation :

Given ,total number of lamps in a hall = 10

And each of them can be switched on independently .

This means that , an every bulbs 2 options either on .

Step 1:

So  , the total numbers of ways will be = 2^{10}

We required at least one lamp is to be switched on to illuminate the hall .

Therefore , there will be only one way when the hall will not be illuminated.

So , the numbers of ways in which the hall can be illuminated

=2^{10} - 1 = 1024 - 1 = 1023

Final answer:

Hence , there are  1023 ways in which the hall can be illuminated.

#SPJ2

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