Math, asked by GoceWolf, 6 months ago

THERE ARE 10 TEAMS IN A BASKETBALL TOURNAMENT, IF EACH TEAMS PLAYS WITH ONE ANOTHER, HOW MAY GAMES ARE THERE IN ONE ELIMINATION ROUND?

Answers

Answered by hema387
3

Perhaps an easier way to do this in your head is

Perhaps an easier way to do this in your head iseach round there are 5 games (2 teams to a game, so 10 / 2 = 5)

Perhaps an easier way to do this in your head iseach round there are 5 games (2 teams to a game, so 10 / 2 = 5)there are 9 rounds to complete one round robin (10 - 1 = 9 opponents)

Perhaps an easier way to do this in your head iseach round there are 5 games (2 teams to a game, so 10 / 2 = 5)there are 9 rounds to complete one round robin (10 - 1 = 9 opponents)5 games x 9 rounds = 45 games for one complete round robin

Perhaps an easier way to do this in your head iseach round there are 5 games (2 teams to a game, so 10 / 2 = 5)there are 9 rounds to complete one round robin (10 - 1 = 9 opponents)5 games x 9 rounds = 45 games for one complete round robindo that 3 times: 3 x 45 = 135

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