Math, asked by madhusmita5547, 16 days ago

there are 100 students in a class. In an examination 50 of them passed in mathematics,45 in physics and 40 in chemistry, 32 passed in exactly 2of these three subjects. find the no of students who passed in all the three subjects.

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Answered by RiyaArmyy7777

Answer:

here I also attached ur ans

Step-by-step explanation:

Given that there are 100 students and only one student passed in all 3 subjects

So the number of students failed in at least one subject is 99

Let a be the number of students failed only in mathematics, b be number of students failed only in physics and c be number of students failed only in Biology.

Let x be number of students failed only in mathematics and physics, y be number of students failed only in physics and biology and z be the number of students failed only in biology and mathematics.

Let p be the number of students failed in all three subjects

By Venn diagram, we get 99=a+b+c+x+y+z+p

Number of students failed in exactly two subjects is 32=x+y+z

Students failed in mathematics is 50=a+x+z+p , students failed in physics is 45=b+x+y+p and students failed in Biology is 40=c+y+z+p

By adding above three equations, we get 135=a+b+c+2(x+y+z)+3p

⇒135=99+32+2p

⇒p=2

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there are 100 students in a class. In an examination 50 of them passed in mathematics,45 in physics and 40 in chemistry, 32 passed in exactly 2of these three subjects. find the no of students who passed in all the three subjects.​

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there are 100 students in a class. In an examination 50 of them passed in mathematics,45 in physics and 40 in chemistry, 32 passed in exactly 2of these three subjects. find the no of students who passed in all the three subjects.