Question

There are 1000 people in a marriage and 1000 pappads. Men need 4 pappads, women need 3 pappads and kids need 1/2 pappad. Then how many are there Men, Women and Kids?

Answer 1

Given:

(i) There are 1000 people in a marriage and 1000 pappads

(ii) Men need 4 pappads, women need 3 pappads and kids need 1/2 pappad.

To find:

(i) How many are there Men, Women and Kids.

Solution:

Let there be x men, y women and z kids.

Total people = 1000.

So,

x + y + z = 1000  ...(1)

Papads consumed by x men = 4x

Papads consumed by y women = 3y

Papads consumed by z kids = z/2

Total papads consumed = 4x + 3y + z/2

This is equal to 1000

So, 4x + 3y + z/2 = 1000

Multiplying by 2, we get,

8x + 6y + z = 2000 ...(2)

Subtracting (1) from (2),

7x + 5y = 1000

⇒ 5y = 1000-7x

⇒ y = 200 - 7x/5

When x = 5,

y = 200 - (7*5)/5

= 200 - 7

= 193

z = 1000-(5+193)

= 802

So, there are 5 men, 193 women and 802 kids.