Question

There are 104 students in class X and 96 students in class IX in a school. In a house examination the students are to be evenly seated in parallel rows such that no two adjacent rows are of the same class.
(a) Find the maximum number of parallel rows of each class for the seating arrangement?

Answer 1

Answer:

There are a total of 200 students (104 and 96).

Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.

a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.

Answer 2

Step-by-step explanation:

HCF of both numbers

factors of 104=2×2×2×13

factors of 96=2×2×2×2×2×3

so, HCF = 2×2×2=8

Therefore, there are 8 parallel rows of each class for the seating arrangement.